3/x^2-50/x=17

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Solution for 3/x^2-50/x=17 equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

3/(x^2)-(50/x) = 17 // - 17

3/(x^2)-(50/x)-17 = 0

3/(x^2)-50*x^-1-17 = 0

3*x^-2-50*x^-1-17 = 0

t_1 = x^-1

3*t_1^2-50*t_1^1-17 = 0

3*t_1^2-50*t_1-17 = 0

DELTA = (-50)^2-(-17*3*4)

DELTA = 2704

DELTA > 0

t_1 = (2704^(1/2)+50)/(2*3) or t_1 = (50-2704^(1/2))/(2*3)

t_1 = 17 or t_1 = -1/3

t_1 = -1/3

x^-1+1/3 = 0

1*x^-1 = -1/3 // : 1

x^-1 = -1/3

-1 < 0

1/(x^1) = -1/3 // * x^1

1 = -1/3*x^1 // : -1/3

-3 = x^1

x = -3

t_1 = 17

x^-1-17 = 0

1*x^-1 = 17 // : 1

x^-1 = 17

-1 < 0

1/(x^1) = 17 // * x^1

1 = 17*x^1 // : 17

1/17 = x^1

x = 1/17

x in { -3, 1/17 }

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